MLE of Normal parameters
[2]:
import numpy as np
import pandas as pd
Recall our first model for spindle length.
\begin{align} l_i \sim \text{Norm}(\phi, \sigma) \;\;\forall i. \end{align}
For this model, we have already worked out analytically that the maximum likelihood estimates for the parameters \(\phi\) and \(\sigma\) are given by their respective plug-in estimates.
\begin{align} &\phi^* = \hat{\phi}\\[1em] &\sigma^* = \hat{\sigma}. \end{align}
We can directly compute these and use parametric bootstrap to get their confidence intervals. We start by loading in the data and computing the MLEs for \(\phi\) and \(\sigma\).
[3]:
df = pd.read_csv(os.path.join(data_path, "good_invitro_droplet_data.csv"), comment="#")
spindle_length = df["Spindle Length (um)"].values
phi_mle = np.mean(spindle_length)
sigma_mle = np.std(spindle_length)
print("φ MLE:", phi_mle, "µm")
print("σ MLE:", sigma_mle, "µm")
φ MLE: 32.86402985074626 µm
σ MLE: 4.784665043782949 µm
Now we use parametric bootstrap to compute the confidence intervals. First, we’ll write functions to perform the bootstrapping.
[4]:
rg = np.random.default_rng()
def draw_parametric_bs_reps(data, phi, sigma, size=1):
"""Parametric bootstrap replicates of parameters of
Normal distribution."""
bs_reps_phi = np.empty(size)
bs_reps_sigma = np.empty(size)
for i in range(size):
bs_sample = np.random.normal(phi, sigma, size=len(data))
bs_reps_phi[i] = np.mean(bs_sample)
bs_reps_sigma[i] = np.std(bs_sample)
return bs_reps_phi, bs_reps_sigma
Now we can get the bootstrap replicates.
[5]:
bs_reps_phi, bs_reps_sigma = draw_parametric_bs_reps(
spindle_length, phi_mle, sigma_mle, size=100000
)
With the bootstrap replicates in hand, we can compute the 95% confidence intervals using percentiles.
[6]:
print('φ conf int:', np.percentile(bs_reps_phi, [2.5, 97.5]))
print('σ conf int:', np.percentile(bs_reps_sigma, [2.5, 97.5]))
φ conf int: [32.5033421 33.22797245]
σ conf int: [4.52513392 5.03823811]
So, we have estimated the parameters under this model.
Computing environment
[7]:
%load_ext watermark
%watermark -v -p numpy,pandas,jupyterlab
Python implementation: CPython
Python version : 3.8.12
IPython version : 7.29.0
numpy : 1.21.2
pandas : 1.3.4
jupyterlab: 3.2.1